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14.6+3.21x+-1.23x^2=0
We add all the numbers together, and all the variables
-1.23x^2+3.21x=0
a = -1.23; b = 3.21; c = 0;
Δ = b2-4ac
Δ = 3.212-4·(-1.23)·0
Δ = 10.3041
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3.21)-\sqrt{10.3041}}{2*-1.23}=\frac{-3.21-\sqrt{10.3041}}{-2.46} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3.21)+\sqrt{10.3041}}{2*-1.23}=\frac{-3.21+\sqrt{10.3041}}{-2.46} $
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